MOBIL BERTEMU SAAT BERJALAN SEARAH!!!!

Mobil berjalan searah yang mempunyai kecepatan berbeda. Mobil 1 dan mobil 2 mempunyai jarak tertentu..Mobil ini akan bertemu pada saat t (waktu) dan jarak s.

mobil-searah1

Penyelesaian:

s = sA – sB

s = (VoA + ½ aA.t2) – (VoB + ½ aB.t2)

s = (VoA – VoB)t + ½ (aA – aB)t2

½ (aA – aB)t2 + (VoA – VoB)t – s = 0 x 2

(aA – aB)t2 + 2(VoA – VoB)t – 2s = 0

2

berdasarkan rumus Vt2 = Vo2 + 2.a.s, maka

3

4

5


~ by swastikayana on March 30, 2009.

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